
T2846b.hs:5:5:
    No instance for (Show (Num a0 => a0))
      arising from a use of `show'
    Possible fix: add an instance declaration for (Show (Num a0 => a0))
    In the expression: show ([1, 2, 3] :: [Num a => a])
    In an equation for `f': f = show ([1, 2, 3] :: [Num a => a])
